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Question

limx0 sin xx________________________________.

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Solution

limx0sinxxL.H.Llimx0-sinxxi.e. limx0-sinxxi.e. -limx0sinxx=-1i.e. left hand limit is -1R.H.Llimx0+sinxxi.e.limx0sinxxi.e. R.H.L=1Since L.H.LR.H.SHence,limx0sinxx does not exist

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