$\lim_{x \to 0} \frac{x^{2 / 3} - 9}{x - 27}$

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Solution

$\lim_{x \to 0} [\frac{x^{2 / 3} - 9}{x - 27}] = \frac{0 - 9}{0 - 27} = \frac{1}{3}$

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