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Question

limx1 sin π xx-1 is equal to

(a) −π

(b) π

(c) -1π

(d) 1π

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Solution

(a) −π
limx1 sin πxx-1=limh0 sin π1+h1+h-1=limh0 sin π+πhh=limh0 -sin πhh=limh0 -sin πhπhπ=-π

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