$\lim_{x \to 3} \frac{\sqrt{2 x + 3}}{x + 3}$

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Solution

$\lim_{x \to 3} [\frac{\sqrt{2 x + 3}}{x + 3}] = \frac{\sqrt{2 \times 3 + 3}}{3 + 3} = \frac{3}{6} = \frac{1}{2}$

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