Line a is parallel to line b and line c is parallel to line d. Then,
A
QR = SP
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B
PQ = RS
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C
QR = PR
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D
SP = RP
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Solution
The correct options are A QR = SP B PQ = RS Consider △PQR and △RSP ∠QRP = ∠SPR (alternate angles) ∠RPQ = ∠PRS (alternate angles) side PR = side RP (common )
△PQR ≅△RSP by Hence, by ASA criterion for congruency of triangles.
Hence QR = SP (corresponding parts of congruent triangles) PQ = RS (corresponding parts of congruent triangles)