Question

Line $l\parallel linem$ and line $n$ is the transmesal the measure of two angles and given the figure. Find the value of $x$

Answer 1

${(3x-25)}^0+{(x+5)}^0={180}^0$ [$\because$ angles are supplementary]

$\therefore$ $4x-{20}^0={180}^0$

$\Rightarrow x=\frac{200}{4}={50}^0$