Line L passes through the points (4, -5) and (3, 7). Find the slope of a line perpendicular to L.

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$\frac{- 1}{2}$

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$\frac{- 1}{12}$

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$\frac{1}{12}$

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Solution

The correct option is D
$\frac{1}{12}$

Slope of line L ( $m_{1})$ = $\frac{(7 - (- 5))}{(3 - 4)} = - 12$
Slope of the line perpendicular to the given line $= - \frac{1}{m_{1}}$

$∴$ Slope of the line perpendicular to L $= \frac{- 1}{- 12} = \frac{1}{12}$

Suggest Corrections

Similar questions

L

(4, - 5)

(3, 7)

L

(3, 1)

(1, 5)

\frac{- 1}{3} .

P (- 3, 7)

m = \frac{1}{2}

G (- 4, 5)

H (- 2, 1)

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