Line L passes through the points (4, -5) and (3, 7). Find the slope of a line perpendicular to L.

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-1/2

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- (1/12)

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1/12

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Solution

The correct option is D
1/12

$Slope of line L is$

$m_{1} =$ $\frac{(7 - (- 5))}{(3 - 4)} = - 12$

Slope of the line perpendicular to the given line = - $\frac{1}{m_{1}}$

Therefore, slope of the line perpendicular to L = $\frac{1}{12}$

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