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Byju's Answer
Standard VIII
Mathematics
Properties of Angles Formed by Two Parallel Lines and a Transversal
Line segment ...
Question
Line segment
P
Q
=
12
c
m
and
R
is a point on it such that
P
R
=
8
c
m
. Then find
P
Q
2
−
P
R
2
.
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Solution
Q
R
=
P
Q
−
P
R
=
12
−
8
=
4
cm
P
Q
2
−
P
R
2
=
(
12
)
2
−
(
8
)
2
=
144
−
64
=
80
cm.
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Similar questions
Q.
In a
Δ
P
Q
R
,
P
R
2
−
P
Q
2
=
Q
R
2
and M is a point on side PR such that
Q
M
⊥
P
R
. Prove that
Q
M
2
=
P
M
×
M
R
Q.
Question 1
In a
Δ
P
Q
R
,
P
R
2
−
P
Q
2
=
Q
R
2
and M is a point on side PR such that
Q
M
⊥
P
R
. Prove that
Q
M
2
=
P
M
×
M
R
.
Q.
In a
△
P
Q
R
,
P
R
2
−
P
Q
2
=
Q
R
2
and
M
is a point on side
P
R
such that
Q
M
⊥
P
R
. Prove that
Q
M
2
=
P
M
×
M
R
.
Q.
Draw a line segment PQ=
8
cm. Take a point R on it such that
l
(
P
R
)
:
l
(
R
Q
)
=
3
:
2
find PR and RQ.
Q.
Draw a line segment PQ of length 7 cm. Mark a point R on it, such that l(PR) : l(RQ) = 4 : 1.