Line nbsp-x-15-y-5-2-z-1-1lies nbsp-on nbsp-the nbsp-plane nbsp-2x-5y-z-5-0 nbsp-TrueFalse

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Condition for a Line to Lie on a Plane

Line nbsp;x...

Question

$Line \frac{x - 1}{5} = \frac{y + 5}{- 2} = \frac{z + 1}{- 1} lies on the plane 2 x + 5 y - z + 5 = 0$

True

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False

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Solution

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Similar questions

Line \frac{x - 1}{5} = \frac{y + 5}{- 2} = \frac{z + 1}{- 1} lies on the plane 2 x + 5 y - z + 5 = 0

2 x + 3 y - 4 z + 5 = 0

x - 5 y + z + 6 = 0

x + y - z + 8 = 0 = x - y - z + 2

\frac{x - 1}{3} = \frac{y - 3}{1} = \frac{z - 4}{- 5}

2 x - y + z + 3 = 0

^{'} k^{'}

\frac{x - 3}{2} = \frac{y + k}{- 1} = \frac{z + 1}{- 5}

2 x - y + z - 7 = 0

5 x + 2 z - 8 = 0

2 x - y + z - 3 = 0

3 x + y + z = 5

2 x - y - 5 z - 3 = 0

3 x + y + z = 5

x - 1 = y + 1 = z - 1

(1, 1, 1)

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