Line x-15-y-5-2-z-1-1lies on the plane 2x-5y-z-5-0

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Condition for a Line to Lie on a Plane

Line x-15=y+5...

Question

$Line \frac{x - 1}{5} = \frac{y + 5}{- 2} = \frac{z + 1}{- 1} lies on the plane 2 x + 5 y - z + 5 = 0$

True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

Line \frac{x - 1}{5} = \frac{y + 5}{- 2} = \frac{z + 1}{- 1} lies on the plane 2 x + 5 y - z + 5 = 0

2 x + 3 y - 4 z + 5 = 0

x - 5 y + z + 6 = 0

x + y - z + 8 = 0 = x - y - z + 2

\frac{x - 1}{3} = \frac{y - 3}{1} = \frac{z - 4}{- 5}

2 x - y + z + 3 = 0

^{'} k^{'}

\frac{x - 3}{2} = \frac{y + k}{- 1} = \frac{z + 1}{- 5}

2 x - y + z - 7 = 0

5 x + 2 z - 8 = 0

2 x - y + z - 3 = 0

3 x + y + z = 5

2 x - y - 5 z - 3 = 0

3 x + y + z = 5

x - 1 = y + 1 = z - 1

(1, 1, 1)

Join BYJU'S Learning Program