MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Properties of Determinants

Linear and Qu...

Question

Linear and Quadralic Equations and Inequalities.
For what values of x does the function $y = | x - 1 | + | x - 3 |$ possess the least value? Find that value.

Open in App

Solution

the function posses least value for the average of the two numbers that is average of 1 and 3, therefore, x=2 is the point at which it will have the least value at $x = 2 y = 2$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Linear and Quadralic Equations and Inequalities.
Prove that if the value of the quadratic trinomial

a x^{2} - b x + c

is an integer for

x_{1} 0, x_{2} = 1, a n d x_{3} = 2,

then the value of the given trinomial is an in teger for any integral x.

Q. Reduce equations to a pair of linear equations and find the value of x and y:

\frac{6}{x} + \frac{1}{y} = 31; \frac{2}{x} + \frac{3}{y} = 16

Q. Find all values of

x

for which the function

y = sin x {cos}^{2} x - 1

assumes the least value. What is that value?

Q. For what value(s) of

λ

, does the pair of linear equations

λ x + y = λ^{2} a n d x + λ y = 1

have a unique solution?

Q. For what values of

a

does the equation

(2 - x) (x + 1) = a

possess real and positive roots?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Properties

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Properties of Determinants

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon