Question

Linear and Quadralic Equations and Inequalities.
Solve the following inequalities.
$|x^2-4x|>1.$

Answer 1

$x^2-4x$ is negative in $0$ to $4$ but when we applied mod it becomes positive

therefore solving the inequality we get

x belongs to $(-\infty ,2-\sqrt{5})\cup (2-\sqrt{3},2+\sqrt{3})\cup (2+\sqrt{5},\infty )$