Lines PQ and RS intersect at O - - POR - - ROQ -5- 7- then - POS is equal toA- 90-B- 100-C- 105-D- 130-

The correct option is C 105o∠POR = 5x, ∠ROQ = 7x. They form linear pair. Hence, 5x + 7x = 180o = gt; x = 15o Then ∠ROQ = 105o∠POS = ∠ROQ = 105o (vertica ...

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Standard IX

Mathematics

Linear Pair

Lines PQ and ...

Question

Lines PQ and RS intersect at O, ∠POR: ∠ROQ = 5:7, then ∠POS is equal to

90^o

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100^o

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105^o

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130^o

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Solution

The correct option is C
105^o

∠POR = 5x, ∠ROQ = 7x.
They form linear pair.
Hence, 5x + 7x = 180^o => x = 15^o
Then ∠ROQ = 105^o∠POS = ∠ROQ = 105^o (vertically opposite angles)

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Lines PQ and RS intersect at O, ∠POR: ∠ROQ = 5:7, then ∠POS is equal to

The correct option is C 105o∠POR = 5x, ∠ROQ = 7x. They form linear pair. Hence, 5x + 7x = 180o => x = 15o Then ∠ROQ = 105o∠POS = ∠ROQ = 105o (vertically opposite angles)

The correct option is C
105^o

∠POR = 5x, ∠ROQ = 7x.
They form linear pair.
Hence, 5x + 7x = 180^o => x = 15^o
Then ∠ROQ = 105^o∠POS = ∠ROQ = 105^o (vertically opposite angles)