MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Pair of Lines

Lines x=y=z...

Question

Lines $x = y = z$ and $x - 2 = y - 3 = z - 5$ aer lines.....(intersecting, parallel, skew)

Open in App

Solution

$\begin{matrix} A c c o r d i n g t o q u e s t i o n, \frac{x - 0}{1} = \frac{y - 0}{1} = \frac{z - 0}{1}, \frac{x - 2}{1} = \frac{y - 3}{1} = \frac{z - 5}{1} ∣ ∣ ∣ ∣ \begin{matrix} 0 - 20 - 30 - 5 111111 \end{matrix} ∣ ∣ ∣ ∣ = 0 ∴ [¯ ¯ ¯ a - ¯ ¯ c ¯ ¯ b ¯ ¯ ¯ d] = 0 T h e r e a r e c o p l a n n e r (I n t e r s e c t) \end{matrix}$

Suggest Corrections

thumbs-up

0

Similar questions

\frac{x}{1} = \frac{y}{2} = \frac{z}{3}

\frac{x - 1}{- 2} = \frac{y - 2}{- 4} = \frac{z - 3}{- 6}

are
(a) coincident
(b) skew
(c) intersecting
(d) parallel

\frac{x}{1} = \frac{y}{2} = \frac{z}{3} and \frac{x - 1}{- 2} = \frac{y - 2}{- 4} = \frac{z - 3}{- 6}

are
(a) parallel
(b) intersecting
(c) skew
(d) coincident

Q. Prove that lines

\frac{x - 1}{3} = \frac{y + 1}{2} = \frac{z - 1}{5}

\frac{x + 2}{4} = \frac{y - 1}{3} = \frac{z + 1}{- 2}

are skew lines.

Q. Prove that the lines

\frac{x - 1}{3} = \frac{y + 1}{2} = \frac{z - 1}{5}

\frac{x + 2}{4} = \frac{y - 1}{3} = \frac{z + 1}{- 2}

\frac{x - 1}{2} = \frac{y - 1}{2} = \frac{z - 2}{3}

\frac{x - 1}{2} = \frac{y - 2}{2} = \frac{z - 3}{- 2}

(Check whether the lines are parallel, mutually perpendicular or intersecting in acute angle)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

A Pair of Straight Lines

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon