Question

Linked Answer Questions 8.20 and 8.21
In the feed drive of a Point-to-Point open loop CNC drive a stepper motor rotating at 200 steps/ rev drives a table though a gear box and lead screw-nut mechanism (pitch=4 mm, number of starts=1). The gear ratio
\(\left(=\dfrac{Output rotational speed}{Input rotational speed }\right)\) is given by \(U=\dfrac{1}{4}\).
The stepper motor (driven by voltage pulses form a pulse generator) executes 1 step/pulse of the pulse generator . The frequency of the pulse train from the pulse generator is \(f=10,000\) pulses per minute.

The Basic Length Unit(BLU), i.e., the table movement corresponding to 1 pulse of the pulse generator, is

Answer 1

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