Linked Comprehensive type
$A = 5 x^{2} - 16 x - 21$
$B = 3 (x + 2)^{2} - 5 (x + 2) + 2$
Sum of the factors of $A$ and $B$ are

(x + 1) (8 x + 17)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x + 1) (8 x - 17)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(x + 1) (5 x - 17)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x + 1) (8 x - 25)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(x + 1) (8 x - 17)$
$A = 5 x^{2} - 16 x - 21$
$B = 3 (x + 2)^{2} - 5 (x + 2) + 2$
factor of A.
$5 x^{2} - 16 x - 21$
$\Rightarrow 5 x^{2} - 21 x + 5 x - 21$
$\Rightarrow x (5 x - 21) + 1 (5 x - 21)$
$\Rightarrow (5 x - 21) (x + 1)$ Ans
factor of B.
$\Rightarrow 3 (x + 2)^{2} - 5 (x + 2) + 2$
$\Rightarrow 3 (x^{2} + 4 + 4 x) - 5 x - 10 + 2$
$\Rightarrow 3 x^{2} + 12 x + 12 - 5 x - 8$
$\Rightarrow 3 x^{2} + 7 x + 4$
$\Rightarrow 3 x^{2} + 4 x + 3 x + 4$
$x (3 x + 4) (x + 1)$ Ans
Sum of factors of A & B.
$\Rightarrow (5 x - 21) (x + 1) + (3 x + 4) (x + 1)$
$\Rightarrow (x + 1) {5 x - 21 + 3 x + 4} = (x + 1) {8 x - 17}$ Ans

Suggest Corrections

Similar questions

A = 5 x^{2} - 16 x - 21

B = 3 (x + 2)^{2} - 5 (x + 2) + 2

B

f (x) = 1 - 2 x + 3 x^{2} - 4 x^{3} + \dots + 17 x^{16} - 18 x^{17}

x^{15}

f (x - 1)

x

\frac{4 x^{2} + 15 x + 17}{x^{2} + 4 x + 12} = \frac{5 x^{2} + 16 x + 18}{2 x^{2} + 5 x + 13}

x

{(\frac{17}{18})}^{x - 1} = {(\frac{18}{17})}^{x - 3}

18 x^{2} - x - 4