Question

Linked Data:
Blind hole $10mm$ diameter, $50mm$ deep are being drilled in steel block, drilling spindle speed is $600rpm$, feed $0.2mm/rev,$ point angle of drill is $120$

During the above operation, the drill wears out after producing $200$ holes.Taylor's tool life equation is of the form $V{T}^{0.3}=C,$ where $V=$ cutting speed in $m/min$ and $T=$ tool life in min. Taylor's constnat $C$ will be

• A. $15$
• B. $72$
• C. $93$
• D. $490$

Answer 1

The correct option is B $72$

Given data:
Number of holes produced/tool $=200$ holes
Tool life $=200\times 0.442=88.33min$

$V=\frac{\pi DN}{1000}=\frac{\pi \times 10\times 600}{1000}=18.84min$

$V{T}^{0.3}=C$
$18.84\times {88.33}^{0.3}=C$
$C=72.26$
$\text{Taylor's tool life constant}C=72.26$