Question

Liquid is filled in a vessel which is kept in a room with temperature ${20}^{o}C$. When the temperature of the liquid is ${80}^{o}C$, then it loses heat at the rate of 60 cal/sec. What will be the rate of loss of heat when the temperature of the liquid is ${40}^{o}C$

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

Rate of loss of heat $\left(\frac{△Q}{t}\right)\propto$ temperature difference $△\theta$
$\frac{(\frac{△Q}{t}{)}_1}{(\frac{△Q}{t}{)}_2}=\frac{△{\theta }_2}{△{\theta }_1}\Rightarrow \frac{60}{(\frac{△Q}{t}{)}_2}=\frac{80-60}{40-20}\Rightarrow (\frac{△Q}{t}{)}_2=\frac{20cal}{sec}$