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Liquids in Liquids

Liquids 'A'...

Question

Liquids $^{'} A^{'}$ and $^{'} B^{'}$ form an ideal solution. Calculate the vapour pressure of solution having 40 mole-percent of $^{'} A^{'}$ in the vapour at equilibrium.
$(P_{A}^{0} = 80 c m H g, P_{B}^{0} = 30 c m H g)$

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Solution

$\frac{1}{P_{t o t a l}} = \frac{Y_{A}}{P_{A}^{0}} + \frac{Y_{B}}{P_{B}^{0}} = \frac{0.4}{80} + \frac{0.6}{30} = \frac{1}{40}$
$P_{t o t a l} = 40 c m H g$

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