List I: 3,6,8,19 List II: x,3,6,8,19 If the median of the numbers in list I above is equal to the median of the numbers in list II above, what is the value of x?
A
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
7
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A7 Median is the middle value of the data values after arranging the data values in the ascending or descending order.
If n is odd, then the median is (n+12)th value.
If n is even, then the median is (n2)th+(n2+1)2th value.
List I:3,6,8,19
Total number of values is n=4 (even) then
the median is (42)th+(42+1)2th
=(2)nd+(3)rd2=6+82=7
List II:x,3,6,8,19
Total number of values is n=5 (odd) then
the median is (5+12)th=3rd value.
Given that median of List I is equal to the median of List II. Therefore, for List II, x=7 should be median value.