Question
List I and List II contains four entries each. Entries of Column I are to be matched some entries of List II. One or more than one entries of List I may match with the same entry of List II.
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Solution
O2(g): ΔfHo=0;ΔfSo=0 as this is elemental form of oxygen.
O3(g): ΔfHo=+ve;ΔfSo=−ve as no. of particle reduced.
Br2(g): ΔfHo=+ve;ΔfSo=+ve as in nature bromine presents in liquid form.
H2O(l): ΔfHo=−ve;ΔfSo=−ve
O3(g): ΔfHo=+ve;ΔfSo=−ve as no. of particle reduced.
Br2(g): ΔfHo=+ve;ΔfSo=+ve as in nature bromine presents in liquid form.
H2O(l): ΔfHo=−ve;ΔfSo=−ve
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