You visited us 1 times! Enjoying our articles? Unlock Full Access!

Oxidation of Alkyl Side Chain

List-I contai...

Question

List-I contains questions related to reaction sequence and List-II contains their answers.

Which of the following options has the correct combination considering reaction in List-I and their product(s) in List-II?

I \to R; I I I \to U

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

I \to Q; I I I \to P

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I \to Q; I I I \to S

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I \to R; I I I \to S

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $I \to R; I I I \to U$

Suggest Corrections

Similar questions

\begin{matrix} List - I & List - II (I) For the reaction & (P) \frac{3}{5} K_{4} [F e (C N)_{6}] \to F e^{3 +} + C O_{2} + N O_{3}^{-} the n-factor is: (II) For the reaction & (Q) 28 F e S_{2} \to F e^{3} + + S O_{2} the n-factor is: (III) For the reaction & (R) 61 B r_{2} + 2 N a O H \to N a B r O_{3} + N a B r + H_{2} O the n-factor is: (IV) For the reaction & (S) 1 A s_{2} S_{3} \to A s^{5 +} + S O_{4}^{2 -} the n-factor is: (T) \frac{5}{3} (U) 11 \end{matrix}

1.0 L

0.01 M

N H_{3}

1.0 M

H C l

p K_{b} (N H_{3}) = 4.74

\begin{matrix} List-I & List-II Volume of HCl added & pOH (I) 2.0 mL & (P) 11.0 (II) 5.0 mL & (Q) 4.14 (III) 10.0 mL & (R) 4.74 (IV) 11.0 mL & (S) 8.37 (T) 8.20 (U) 11.35 \end{matrix}

\begin{matrix} List-I & List-II (I) & Molarity (mol/L) & (P) & 20 (I I) & Molality (mol/kg) & (Q) & 0.67 (I I I) & % mass by mass & (R) & 1.2 (I V) & % mass by volume (g/ml) & (S) & 1 (T) & 25 (U) & 1.25 \end{matrix}

\begin{matrix} List-I & List-II (I) & Teflon & (P) & Electrically insulated buttons (II) & Vinyl Rubber & (Q) & Pipe Insulation (III) & Lexan & (R) & Rubber Erasers (IV) & PVC & (S) & Bullet proof glass (T) & Foam thermocole (U) & Non-stick kitchenware \end{matrix}

Join BYJU'S Learning Program