The correct option is
D A - iv, B - iii, C - i, D - ii
Nitrobenzene can be reduced by using various products.
The products of reduction depend on the reducing agent used.
Reduction of nitrobenzene with tin in presence of HCl gives aniline (aminobenzene).
C6H5NO2 Sn + HCl−−−−−−→C6H5NH2
Reduction of nitrobenzene with zinc in presence of ammonium chloride gives phenyl hydroxyl amine.
C6H5NO2 Zn + NH4Cl−−−−−−−−→C6H5NHOH
Reduction of nitrobenzene with lithium aluminum hydride gives azobenzene.
C6H5NO2 Zn + NH4Cl−−−−−−−−→C6H5−N=N−C6H5
Reduction of nitrobenzene with zinc in the presence of alcoholic potassium hydroxide gives hydrazobenzene.
C6H5NO2 Zn + KOH−−−−−−−→C6H5−HN−NH−C6H5