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Question

List-I List-II
A) Vertex of the parabola y2−x+4y+5=0p) (1,4)
B) Focus of the parabola x2−2x−12y+13=0q). (1,-2)
C) The directrix of the parabola x2+4x+2y−8=0r) 2y-13=0
D) Normal at (1,1) to y2=xs) 2x+y-3=0
Match the following

A
A-q, B-p, C-r, D-s
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B
A-p, B-q, C-r, D-s
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C
A-s, B-q, C-p, D-r
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D
A-r, B-p, C-q, D-s
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Solution

The correct option is A A-q, B-p, C-r, D-s
a)(y+2)2=(x1)

Vertex=(1,2)

b)x22x12y+13=0

(x1)2=12(y1)

Vertex = (1,1)

a=3

focus = (1,1+3)

=(1,4)

c)(x+2)2=2(y6)

Vertex = (2,6)

a=12

(y6)=a

y6=12

y=6+12

2y=13

d)dydx=12y=12 slope of normal=2

(y1)=2(x1)

2x+y=3

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