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Byju's Answer
Standard XII
Mathematics
General Solution of Trigonometric Equation
List-IList-II...
Question
List-I
List-II
1
)
tan
2
θ
=
1
a
)
n
π
±
π
/
6
2
)
cos
2
θ
=
1
4
b
)
n
π
±
π
/
4
3
)
sin
2
θ
=
1
4
c
)
n
π
±
π
/
3
4) cosec
θ
=
1
d)
n
π
±
π
/
2
e
)
n
π
±
π
/
8
A
b,d,a,c
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B
c,a,e,b
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C
b,c,a,d
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D
d,a,b,c
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Solution
The correct option is
C
b,c,a,d
1
]
t
a
n
2
θ
=
1
means
θ
=
n
π
+
Π
4
........
t
a
n
π
4
=
1
2
]
c
o
s
2
θ
=
1
4
means
c
o
s
θ
=
±
1
2
means
θ
=
n
π
±
π
3
3
]
s
i
n
2
θ
=
1
4
means
s
i
n
θ
=
±
1
2
means
θ
=
n
π
±
π
6
4
]
c
o
s
e
c
2
θ
=
1
means
c
o
s
e
c
θ
=
±
1
means
θ
=
n
π
±
π
2
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Q.
Solve the equation:
√
(
1
16
+
c
o
s
4
x
−
1
2
c
o
s
2
x
)
+
√
(
9
16
+
c
o
s
4
x
−
3
2
c
o
s
2
x
)
=
1
2