The correct option is
B I-d, II-a, III-b, IV-c
Azimuthal quantum number
l describes the shape of orbitals occupied by the electrons.
1) When
l=0 the orbital is spherical, i.e.,
s is the orbital. When
l=0, the magnetic quantum number
m=0, so there is only one such orbital for each value of
n. Then,
Ψ2 depends only on distance
r from the nucleus and is same in all directions.
2) When l=1, the orbital is p orbital. When l=1, the magnetic quantum number m=(2l+1)=3(−1,0,+1). There are therefore three orbitals which are identical in energy, shape and size, which differ only in their direction in space. So, for this group, solution to wave equation Ψ2 depends both on distance from nucleus r and only one direction in space (x,y,z). These three solution to wave equation may be written as :
Ψx=f(r).f(x)
Ψy=f(r).f(y)
Ψz=f(r).f(z)
3) When l=2, the orbital is d orbital. When l=2, the magnetic quantum number m=(2l+1)=5(−2,−1,0,+1,+2). There are therefore five orbitals. So, for this group, solution to wave equation Ψ2 depends both on distance from nucleus r and any two directions in space (x,y,z). These solutions to wave equation may be written as for example, Ψx=f(r).f(x).f(y).
4) When l=3, the orbital is f orbital. When l=3, the magnetic quantum number m=(2l+1)=7(−3,−2,−1,0,+1,+2,+3). There are therefore seven orbitals. So, for this group, solution to wave equation Ψ2 depends both on distance from nucleus r and three direction in space (x,y,z). These solution to wave equation may be written as for example Ψx=f(r).f(x).f(y).f(z).