List-I List-ll
(A) $O_{3}$ (1) Turns benzidine paper to brown
(B) Hypo
(2) Turns anhydrous ${C u S O}_{4}$ to blue
(C) $H_{2} O$ (3) Violet colour with $F e C l_{3}$
(D) $H_{2} S$ (4) Rotten egg smell
The correct match is :

A-2, B-3, C-1, D-4

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A-4, B-2, C-3, D-1

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A-1, B-3, C-2, D-4

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A-3, B-4, C-2, D-1

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Solution

The correct option is C A-1, B-3, C-2, D-4
$O_{3}$ turns benzidine paper to brown colour.
Hypo gives violet colour with $F e C l_{3}$ .
Water ( $H_{2} O$ ) turns anhydrous $C u S O_{4}$ blue by forming pentahydrate. The reaction is as follows $C u S O_{4} + H_{2} O \to C u S O_{4} .5 H_{2} O$
$H_{2} S$ has rotten egg smell.

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List-I	List-ll
(A) $O_{3}$	(1) Turns benzidine paper to brown
(B) Hypo	(2) Turns anhydrous ${C u S O}_{4}$ to blue
(C) $H_{2} O$	(3) Violet colour with $F e C l_{3}$
(D) $H_{2} S$	(4) Rotten egg smell

List-IList-ll(A) O3(1) Turns benzidine paper to brown(B) Hypo(2) Turns anhydrous CuSO4 to blue(C) H2O(3) Violet colour with FeCl3(D) H2S(4) Rotten egg smellThe correct match is :

The correct option is C A-1, B-3, C-2, D-4O3 turns benzidine paper to brown colour.Hypo gives violet colour with FeCl3.Water (H2O) turns anhydrous CuSO4 blue by forming pentahydrate. The reaction is as follows CuSO4+H2O→CuSO4.5H2OH2S has rotten egg smell.

List-I List-ll
(A) $O_{3}$ (1) Turns benzidine paper to brown
(B) Hypo
(2) Turns anhydrous ${C u S O}_{4}$ to blue
(C) $H_{2} O$ (3) Violet colour with $F e C l_{3}$
(D) $H_{2} S$ (4) Rotten egg smell
The correct match is :