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Question

List one gives certain physical quantity and List - II gives there magnitude.



List - IList - II(I) Acceleration of 2 kg(P) 0(II) Acceleration of 4 kg(Q) 3(III) Acceleration of 6 kg(R) 6(IV) Friction between 2 kg & 4 kg(S)83(T)163(U)185
If external force of 40 N is applied horizontly on 4 kg block, Correct match for acceleration and friction is

A
IQ;IIS;IIIP;IVR
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B
IS;IIS;IIIP;IVT
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C
IQ;IIQ;IIIP;IVR
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D
IR;IIQ;IIIS;IVP
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Solution

The correct option is B IS;IIS;IIIP;IVT
Limiting friction between 2 kg & 4 kg is f24=6N
Limiting friction between 4 kg & 6 kg is f46=24N
Which means, the maximum force the 4 kg block can apply on the 6 kg block is 24 N.
However, the limiting friction between 6 kg & ground is f6=24N. This means, the 6 Kg block will not move.
The two possible cases are,
The 2 kg and 4 kg blocks move together or they slip between each other.
Say, they move together, then
a=40242+4=83
The net force on 2 kg block is 2×83=163=5.33
This is less than the limiting friction. So, they two blocks move together, and the acceleration was found to be 83.


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