List the elements in order of increasing atomic radius.

K < N a < S i

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S i < N a < K

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N a < S i < K

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S i < K < N a

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Solution

The correct option is B $S i < N a < K$
The atomic size increases down the group. $N a$ and $K$ belongs to same group. Hence $N a < K$ . Also atomic size decreases along a period and $N a$ and $S i$ belong to same period. $∴$ $N a > S i$ . On combining, the final order is $S i < N a < K$ i.e., option B.

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List the elements in order of increasing atomic radius.

The correct option is B Si<Na<KThe atomic size increases down the group. Na and K belongs to same group. Hence Na<K. Also atomic size decreases along a period and Na and Si belong to same period. ∴ Na>Si. On combining, the final order is Si<Na<K i.e., option B.