Question

List the highest value of element from the following set .

{$x$ : $x^2-2x-3=0$}

Answer 1

We have, $x^2-2x-3=0$

$\Rightarrow x^2-3x+x-3=0$

$\Rightarrow x(x-3)+(x-3)=0$

$\Rightarrow (x-3)(x+1)=0$

$\Rightarrow x=3,-1$

Hence, elements of the set $=3,-1$.

$\therefore$ Highest value among these numbers is $3$.