Lithium aluminium hydride acts as:

oxidising agent

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complex formating agent

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reducing agent

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both oxidant and reductant

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Solution

The correct option is B reducing agent
$L i A l H_{4}$ is used as a reducing agent.
For example,
$H_{3} C - C^{} H O H_{3} O^{+} - --- \to L i A l H_{4} H_{3} C - C^{} H_{2} O H$
The star marked carbon gets reduced.

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Similar questions

L l A l H_{4}

H N O_{2}

H N O_{3}

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