Lithium aluminium hydride reacts with silicon tetrachloride to form?

L i C l,

A l H_{3}

and

S i H_{4}

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L i C l,

A l C l_{3}

and

S i H_{4}

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L i H,

A l C l_{3}

and

S i C l_{2}

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L i H,

A l H_{3}

and

S i H_{4}

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Solution

The correct option is B $L i C l,$ $A l C l_{3}$ and $S i H_{4}$
Lithium aluminium hydride reacts with silicon tetrachloride to form LiCl (lithium chloride),
$A l C l_{3}$ (aluminum trichloride ) and $S i H_{4}$ (silicon hydride).
$S i C l_{4} + L i A l H_{4} \to L i C l + A l C l_{3} + S i H_{4}$

Hence, option B is correct.

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Similar questions

L i H + A l H_{3} ⟶ L i A l H_{4}

A l H_{3}

L i H

Look at the following reaction:
$L i H + A l H_{3} ⟶ L i A l H_{4}$

Here $A l H_{3}$ and $L i H$ act as:

[C H_{4}, H_{2} S, P H_{3} a n d S i H_{4}]

Look at the following reaction:
$L i H + A l H_{3} ⟶ L i A l H_{4}$

Here $A l H_{3}$ and $L i H$ act as:

H_{2} O, N H_{3}, B F_{3}

S i H_{4}

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