A metal has a fcc lattice. The edge length of the cell is 404 pm. The density of the metal is $2.72 g c m^{- 3}$ . The molar mass of the metal is
( $N_{A}$ Avogadro's constant = $6.02 \times 10^{23} m o l^{- 1}$ )

A metal has a fcc lattice . The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm^-3. The molar mass of the metal is:

(N_A Avogadro's constant =6.02×10²³ mol^-1)

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Lithium has a BCC structure. Its density is 530 kg m−3 and its atomic mass is 6.94 g mol–1. Calculate the edge length of a unit cell of Lithium metal (NA=6.02×1023 mol−1)

The correct option is A 352 pm d=z×Ma3×NA z is 2 here since this is BCC. 0.53g/cm3=2×6.94(g/mol)a3×6.02×1023mol−1 a3=43.5×10−24 cm3 a=3.52×10−8 cm=352 pm

Lithium has a BCC structure. Its density is 530 kg $m^{- 3}$ and its atomic mass is 6.94 g $m o l^{- 1}$ . Calculate the edge length of a unit cell of Lithium metal $(N_{A} = 6.02 \times 10^{23} m o l^{- 1})$

The correct option is A
352 pm

$d = \frac{z \times M}{a^{3} \times N_{A}}$

z is 2 here since this is BCC.

$0.53 g / c m^{3} = \frac{2 \times 6.94 (g / m o l)}{a^{3} \times 6.02 \times 10^{23} m o l^{- 1}}$
$a^{3} = 43.5 \times 10^{- 24} c m^{3}$
$a = 3.52 \times 10^{-} 8 c m = 352 p m$