Littles law can be applied to any part of the store, such as a particular department or the checkout lines. The store owner determines that, during business hours, approximately $84$ shoppers per hour make a purchase and each of these shoppers spend an average of $5$ minutes in the checkout line. At any time during business hours, about how many shoppers, on average, are waiting in the checkout line to make a purchase at the Good Deals Store?

7

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6

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5

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4

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Solution

The correct option is A $7$
Given : $r$ is shoppers/minute
$T$ is average time spend by shoppers in minutes
$N$ average number of shoppers.

Here, shoppers/hour $= 84$ .
Hence $r = \frac{84}{60}$
$T = 5$
Hence $N = r T = \frac{84}{60} \times 5 = 7$

Average number of shoppers waiting at checkout $= 7$

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The correct option is A 7Given : r is shoppers/minuteT is average time spend by shoppers in minutesN average number of shoppers.Here, shoppers/hour =84.Hence r=8460T=5Hence N=rT=8460×5=7Average number of shoppers waiting at checkout =7