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B
f(x)=lnx in [1,e]
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C
f(x)=x−1x in [1,3]
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D
f(x)=√x2−4 in [2,4]
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Solution
The correct option is Df(x)=√x2−4 in [2,4] |x| is not differentiable at x=0. So, LMVT can't be applied.
All the remaining options satisfy the LMVT conditions.