$L n^{3 +}$ (trivalent lanthanides ions) have EC

[X e] 4 f^{1} t o [X e] 4 F^{14}

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[X e] 4 d^{1} 4 f^{1} t o [X e] 4 d^{1} 4 F^{14}

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[X e] 4 d^{2} 4 f^{0} t o [X e] 4 d^{1} 4 F^{14}

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[X e] 4 f^{0} t o [X e] 4 F^{14}

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Solution

The correct option is A $[X e] 4 f^{1} t o [X e] 4 F^{14}$
Lanthanides have configuration of
$[X e] 4 F^{1 - 14} 5 d^{1} 6 s^{2}$
So their trivalent ion have configuration of
$[X e] 4 f^{1} t o [X e] 4 F^{14}$

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Ln3+ (trivalent lanthanides ions) have EC

The correct option is A [Xe]4f1to[Xe]4F14Lanthanides have configuration of[Xe]4F1−145d16s2So their trivalent ion have configuration of[Xe]4f1to[Xe]4F14

$L n^{3 +}$ (trivalent lanthanides ions) have EC

The correct option is A $[X e] 4 f^{1} t o [X e] 4 F^{14}$
Lanthanides have configuration of
$[X e] 4 F^{1 - 14} 5 d^{1} 6 s^{2}$
So their trivalent ion have configuration of
$[X e] 4 f^{1} t o [X e] 4 F^{14}$