Question

ln a chemical equilibrium, the rate constant for the backward reaction is $7.5\times {10}^{-4}$ and the equilibrium constant is 1.5 the rate constant for the forward reaction is:

• A. $2\times {10}^{-3}$
• B. $5\times {10}^{-4}$
• C. $1.12\times {10}^{-3}$
• D. $9.0\times {10}^{-4}$

Answer 1

The correct option is C $1.12\times {10}^{-3}$

$K=\frac{K_f}{K_b}$

$K_f=K_b{K}_c=7.5\times 1.5\times {10}^{-4}=1.12\times {10}^{-3}$