Locate -17 on the number line-

Here,17 = 4^2 +1 So, draw a right angled Δ OAB, in which OA = 4 units and AB = 1 unit and ∠ OAB = 90^∘ By using Pythagoras theorem, we get OB=√(OA^2+AB^2)=√(4^2 ...

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Byju's Answer

Standard IX

Mathematics

Representation of Irrational Numbers on the Number Line

Locate √17 on...

Question

Locate $\sqrt{17}$ on the number line.

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Solution

Here, $17 = 4^{2} + 1$
So, draw a right angled $Δ O A B$ , in which OA = 4 units and AB = 1 unit and $∠ O A B = 90^{\circ}$
By using Pythagoras theorem, we get
$O B = \sqrt{O A^{2} + A B^{2}} = \sqrt{4^{2} + 1^{2}} = \sqrt{16 + 1} = \sqrt{17}$

Taking $O B = \sqrt{17}$ as radius and point O as centre, draw an arc which meets the number line at point P on the positive side of it. The point P represents $\sqrt{17}$ on the number line.

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Locate √17 on the number line.

Locate $\sqrt{17}$ on the number line.