Locate the complex number z=x+iy for which log1/3{log1/2(|z|2+4|z|+3)}<0
A
Empty set
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
circle of radius 6 and center at origin
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
circle of radius 3 and center at origin
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
circle of radius 2 and center at origin
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A Empty set log1/3{log1/2(|z|2+4|z|+3)}<0 ⇒log1/2(|z|2+4|z|+3)>0 ⇒|z|2+4|z|+3<0 ⇒(|z|+1)(|z|+3)<0 Since, |z|+1>0 and |z|+3>0 Therefore, z belongs to empty set. Ans: A