Locate the image of the point object O in the situation shown in the figure. The point C denotes the centre of curvature of the separating surface.

30 cm, left

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30 cm, right

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20 cm, right

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20 cm, right

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Solution

The correct option is A 30 cm, left
Here u = -15 cm, R = 30 cm, $μ_{1}$ = 1.0 and $μ_{2}$ = 1.5.
We have,
$\frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R}$
$o r, \frac{1.5}{v} - \frac{1.0}{- 15 c m} = \frac{1.5 - 1}{30 c m}$
$o r, \frac{1.5}{v} = \frac{0.5}{30 c m} - \frac{1}{15 c m}$
$o r, v = - 30 c m .$
The image is formed 30 cm left to the spherical surface and is virtual.

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Locate the image of the point object O in the situation shown in the figure. The point C denotes the centre of curvature of the separating surface.

The correct option is A 30 cm, leftHere u = -15 cm, R = 30 cm, μ1 = 1.0 and μ2 = 1.5. We have, μ2v−μ1u=μ2−μ1R or, 1.5v−1.0−15 cm=1.5−130 cm or, 1.5v=0.530 cm−115 cm or, v=−30 cm. The image is formed 30 cm left to the spherical surface and is virtual.