Locate the image of the point P as seen by the eye in the figure (18-E5).

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Solution

Position of point P, $\frac{d}{μ_{o}} = \frac{t_{1}}{μ_{1}} + \frac{t_{2}}{μ_{2}} + . . . . .$
Or $\frac{d}{1} = \frac{0.4}{1.4} + \frac{1}{1} + \frac{0.3}{1.3} + \frac{1}{1} + \frac{0.2}{1.2} + \frac{1}{1}$
$⟹ d = 3.7 c m$

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Locate the image of the point P as seen by the eye in the figure (18-E5).

Position of point P, dμo=t1μ1+t2μ2+.....Or d1=0.41.4+11+0.31.3+11+0.21.2+11⟹ d=3.7 cm

Position of point P, $\frac{d}{μ_{o}} = \frac{t_{1}}{μ_{1}} + \frac{t_{2}}{μ_{2}} + . . . . .$
Or $\frac{d}{1} = \frac{0.4}{1.4} + \frac{1}{1} + \frac{0.3}{1.3} + \frac{1}{1} + \frac{0.2}{1.2} + \frac{1}{1}$
$⟹ d = 3.7 c m$