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Question

Locus of a point P which such that PA=PB where A=(0,3,2) and B=(2,4,1) is

A
2x+yz=4
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B
x2y+z+1=0
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C
9x2y+4z5=0
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D
None of these
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Solution

The correct option is A 2x+yz=4
Let the co-ordinate of P be (x,y,z).
Given the points A(0,3.2) and B(2,4,1).
Given,
PA=PB.
or, x2+(y3)2+(z2)2=(x2)2+(y4)2+(z1)2
or, 6y+94z+4=4x+48y+162z+1 [ Squaring and then eliminating the higher power of x,y,z]
or,4x+2y2z=8
or, 2x+yz=4.
So locus of P is 2x+yz=4.

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