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Byju's Answer
Standard XII
Mathematics
Pole and Polar of a Circle
Locus of mid-...
Question
Locus of mid-point of chord of the circle
x
2
+
y
2
=
r
2
passing through (h, k).
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Solution
Let coordinates of Mid-point be
(
l
,
m
)
Curve=>
x
2
+
y
2
=
r
2
Equation of chord whose mid-points given=>
l
x
+
m
y
−
r
2
=
l
2
+
m
2
−
r
2
=
>
l
x
+
m
y
=
l
2
+
m
2
(
h
,
k
)
lies on =>
l
h
+
m
k
=
l
2
+
m
2
for locus
l
→
x
,
m
→
y
Required locus=>
h
x
+
k
y
=
x
2
+
y
2
=
>
x
2
+
y
2
−
h
x
−
k
y
=
0
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Similar questions
Q.
Find the locus of the middle points of chords of the circle
x
2
+
y
2
=
a
2
which pass through the fixed point
(
h
,
k
)
.
Q.
Through a point
(
h
,
k
)
secants are drawn to the circle
(
x
2
+
y
2
)
=
r
2
. The mid-points of the corresponding chords describe the curve
Q.
Through a fixed point
(
h
,
k
)
secants are drawn to the circle
x
2
+
y
2
=
r
2
Then the locus of the midpoints of the chords intercepted by the circle is
Q.
Find the locus of mid point of chord of
x
2
+
y
2
+
2
g
x
+
2
f
y
+
c
=
0
that pass through the origin.
Q.
STATEMENT - 1 : Locus of mid point of chords of circle
x
2
+
y
2
=
4
which subtends angle of
π
2
at origin is
x
2
+
y
2
=
1.
STATEMENT - 2 : If any chord of circle
x
2
+
y
2
=
r
2
subtends an angle
′
θ
′
at center, then its mid point always lies on
x
2
+
y
2
=
r
2
cos
2
(
θ
2
)
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