Locus of mid point of chords of x2+y2+2gx+2fy+c=0 that pass through the origin, is
A
x2+y2+2gx+2fy+c=0
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B
x2+y2+gx+fy+c=0
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C
x2+y2+gx+fy=0
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D
2(x2+y2+gx+fy)+c=0
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Solution
The correct option is Cx2+y2+gx+fy=0 Let the mid point of chords of circle be P(h,k).
Equation of this chord is T=S1 xh+yk+g(x+h)+f(y+k)+c=h2+k2+2gh+2fk+c.
It passes through (0,0) ⇒h2+k2+gh+fk=0
Hence required locus is x2+y2+gx+fy=0