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Question

Locus of the point whose sum of distances from the origin and the x axis is 4 units is

A
x2=8(2y),y0
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B
x2=8(2+y),y0
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C
x2=8(2+y),y<0
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D
x2=8(2y),y<0
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Solution

The correct option is C x2=8(2+y),y<0
Let P(x,y) be a point which satisfies the given condition
x2+y2+|y|=4
when y0 then
x2+y2=4y
x2+y2=168y+y2
x2=8(2y)
when y<0
x2+y2y=4
x2+y2=4+y
x2+y2=16+8y+y2
x2=8(2+y)

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