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Byju's Answer
Standard XII
Mathematics
Properties of Modulus
Locus of the ...
Question
Locus of the point z satisfying the equation
|
z
−
1
|
+
|
z
−
i
|
=
√
2
is
A
Circle
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B
A straight line
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C
Point
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D
Complex
x
−
y
plane
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Solution
The correct option is
B
A straight line
Given
|
z
−
1
|
+
|
z
−
i
|
=
√
2
Also, we know that if
|
z
−
z
1
|
+
|
z
−
z
2
|
=
2
k
represents a straight line when
|
z
1
−
z
2
|
=
2
k
.
In given equation
|
z
1
−
z
2
|
=
|
1
−
i
|
=
√
2
=
2
k
.
So, above equation represents a straight line.
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