wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

log(1+3i) can be expressed in cartesian form as

A
ln2(2π3)i
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
ln2+(2π3)i
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
ln2(π3)i
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
ln2+(π3)i
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B ln2+(2π3)i
log(z)=ln(|z|)+iarg(z)

For z=1+3i,|z|=2 and
tanα=31
α=π3
arg(z)=θ=ππ3=2π3

Hence, log(1+3i)=ln2+(2π3)i

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Logarithm of a Complex Number
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon