${log}_{10} 5 + {log}_{10} 8 - 2 {log}_{10} 2$ =

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{log}_{10} 2

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Solution

The correct option is C 1
Given ${log}_{10} 5 + {log}_{10} 8 - 2 {log}_{10} 2$
[We know ${log}_{a} m + l o g_{a} n = l o g_{a} m n$ ]
= ${log}_{10} 5 \times 8 - 2 {log}_{10} 2$
[As $l o g_{a} n^{m} = m l o g_{a} n$ ]
= ${log}_{10} 5 \times 8 - {log}_{10} 4$
[Also ${log}_{a} \frac{m}{n} = l o g_{a} m - l o g_{a} n$ ]
= ${log}_{10} \frac{40}{4}$
= ${log}_{10} 10 = 1$

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Similar questions

\frac{{l o g}_{10} 8}{{l o g}_{10} 2} = ?

{log}_{10} 8 = 0.90

log 0.125

2 {log}_{10} 5 + {log}_{10} 8 - \frac{1}{2} {log}_{10} 4

{log}_{10} 5 + 2 {log}_{10} 4

{log}_{10} 8

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