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Question

log10(x+1)+log10(x1)=log1011+2log103
Calculate the value of x.

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Solution

log10(x+1)+log10(x1)=log1011+2log103
We know logam+logan=logamn and
nlogam=logamn
Hence
log10(x+1)×(x1)=log1011×9
log10(x21)=log1099
Comparing LHS and RHS
x21=99
x2=100
x=10

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